1.5^2=x^2+x^2

Solution for 1.5^2=x^2+x^2 equation:

1.5^2=x^2+x^2

We move all terms to the left:

1.5^2-(x^2+x^2)=0

We add all the numbers together, and all the variables

-(x^2+x^2)+2.25=0

We get rid of parentheses

-x^2-x^2+2.25=0

We add all the numbers together, and all the variables

-2x^2+2.25=0

a = -2; b = 0; c = +2.25;
Δ = b2-4ac
Δ = 02-4·(-2)·2.25
Δ = 18
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18}=\sqrt{9*2}=\sqrt{9}*\sqrt{2}=3\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{2}}{2*-2}=\frac{0-3\sqrt{2}}{-4}
=-\frac{3\sqrt{2}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{2}}{2*-2}=\frac{0+3\sqrt{2}}{-4}
=\frac{3\sqrt{2}}{-4}
$